10 ~mL of 2(M) ~NaOH solution is added to 200 ~mL of 0.5 (M) of NaOH solution. What is the final concentration ?

Correct answer: A. 0.57(M) From molarity equation aligned & M_1 V_1+M_2 V_2=MV_ (total) & 2 × (10)/(1000)+0.5 × (200)/(1000)=M × (210)/(1000) & 120=M × 210 & M=(120)/(210)=0.57 M aligned

JEE Main 201325 AprilOnline

Exam: JEE Main
Year: 2013
Date: 25 April
Mode: Online
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2013 · 25 April · Online · Chemistry · Some Basic Concepts of Chemistry

10 ~mL of 2(M) ~NaOH solution is added to 200 ~mL of 0.5 (M) of...

10 \mathrm{~mL}

2(\mathrm{M}) \mathrm{~NaOH}

solution is added to

200 \mathrm{~mL}

0.5

\mathrm{(M)}

\mathrm{NaOH}

solution. What is the final concentration ?

Options

A $0.57(\mathrm{M})$
B $5.7(\mathrm{M})$
C $11.4(\mathrm{M})$
D $1.14(\mathrm{M})$

Correct answer

A. $0.57(\mathrm{M})$

Step-by-step solution

From molarity equation

\begin{aligned} & \mathrm{M}_1 \mathrm{V}_1+\mathrm{M}_2 \mathrm{V}_2=\mathrm{MV}_{\text{(total) }} \\ & 2 \times \frac{10}{1000}+0.5 \times \frac{200}{1000}=\mathrm{M} \times \frac{210}{1000} \\ & 120=\mathrm{M} \times 210 \\ & \mathrm{M}=\frac{120}{210}=0.57 \mathrm{ M} \end{aligned}

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