JEE Main2013ChemistrySome Basic Concepts of ChemistryActual
The density of 3 M solution of sodium chloride is 1.252 ~g ~mL ⁻¹ . The molality of the solution will be : ( . molar mass, . NaCl =585 ~g ~mol ⁻¹ )
Options
- A260 ~m
- B2.18 ~m
- C2.79 ~m
- D3.00 ~m
Correct answer
C. 2.79 ~m
Step-by-step solution
The relation between molarity (M) and molality (m) is d= M ( 1 m + M ₂ 1000 ), M ₂= Mol. mass of solute On putting value 1.252=3 ( 1 m + 58.5 1000 ) on solving m=2.79