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JEE Main 2012Offline

Exam: JEE Main
Year: 2012
Mode: Offline
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2012 · Offline · Chemistry · Some Basic Concepts of Chemistry

The density of a solution prepared by dissolving 120 ~g of urea...

The density of a solution prepared by dissolving

120 \mathrm{~g}

of urea (mol. Mass

=60 \mathrm{u}

) in

1000 \mathrm{~g}

of water is

1.15 \mathrm{~g} / \mathrm{mL}

. The molarity of this solution is :

Options

A $0.50 \mathrm{~M}$
B $1.78 \mathrm{~M}$
C $1.02 \mathrm{~M}$
D $2.05 \mathrm{~M}$

Correct answer

D. $2.05 \mathrm{~M}$

Step-by-step solution

Total weight of solution

=1000+120=1120 \mathrm{ g} \text{ Molarity }=\frac{120}{60} \times \frac{1000}{1120 / 1.15}=2.05

\mathrm{ M}

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