The density (in g ~mL ⁻¹ ) of a 3.60 ~M sulphuric acid solution that is 29 % ~ H ₂ SO ₄ (Molar mass =98 ~g mol ⁻¹ ) by mass will be

Step-by-step solution

Let the density of solution be ' d ' Molarity of solution given =3.6 i.e. 1 litre of solution contains 3.6 moles of H ₂ SO ₄ or 1 litre of solution contains 3.6 98 ~gms of H ₂ SO ₄ Since, the solution is 29 % by mass. 100 ~gm solution contains 29 ~gm ~H ₂ SO ₄ 100 ~d ml solution contains 29 ~gm of H ₂ SO ₄1000 ~ml solution contains 3.6 98 ~gm of H ₂ SO ₄ 3.6 98= 29 d 100 1000d=1.22 Hence, (C) is correct.