JEE Main2004ChemistrySome Basic Concepts of ChemistryActual
To neutralize completely 20 ~mL of 0.1 M aqueous solution of phosphorous acid ( H ₃ PO ₃ ) , the volume of 0.1 M aqueous KOH solution required is
Options
- A10 ~mL
- B60 ~mL
- C40 ~mL
- D20 ~mL
Correct answer
C. 40 ~mL
Step-by-step solution
No. of gm equivalents of phosphorous acid = No . of gm equivalents of KOH aligned & 20 0.1 2(n= factor )=0.1 V & =0.1 V aligned V = 4 0.1 =40 ml