A sealed flask with a capacity of 2 dm ^ 3 contains 11g of propane...

Real gases behave ideally at high temperature and low pressure.

Number of moles of propane gas, ${C}_{3}{H}_{8} = \dfrac{11}{44} = 0 . 25$ moles

$PV = nRT$

P=Pressure=$2MPa$

V=Volume=$2{dm}^{3}$

n=Number of moles

T=Temperature

$⇒ 2 \times {10}^{6} \times 2 \times {10}^{- 3} = 0 . 25 \times 8 . 3 \times T$

$⇒ T = 1927 . 710K = 1654 . 56 ° C$