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A sealed flask with a capacity of 2 dm 3 contains 11 g of propane gas. The flask is so weak that it will burst if the pressure becomes 2 MPa . The minimum temperature at which the flask will burst is C ∘ . [Nearest integer] (Given: R = 8 . 3 J K - 1 mol - 1 . Atomic masses of C and H are 12 u and 1 u respectively.) (Assume that propane behaves as an ideal gas.)

Correct answer

0

Step-by-step solution

Real gases behave ideally at high temperature and low pressure. Number of moles of propane gas, C 3 H 8 = 11 44 = 0 . 25 moles PV = nRT P=Pressure= 2 MPa V=Volume= 2 dm 3 n=Number of moles T=Temperature ⇒ 2 × 10 6 × 2 × 10 - 3 = 0 . 25 × 8 . 3 × T ⇒ T = 1927 . 710   K = 1654 . 56   ° C

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