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JEE Main202225 Jul 2022Morning ShiftChemistryStates of MatterActual

The pressure of a moist gas at 27 ° C is 4 atm . The volume of the container is doubled at the same temperature. The new pressure of the moist gas is … × 10 - 1 atm. (Nearest integer) (Given: The vapour pressure of water at 27 ° C is 0 . 4 atm )

Correct answer

0

Step-by-step solution

Dalton's Law states that the total pressure P of moist air is the sum of partial pressures of dry air P a and water vapor P v : P =   P a + P v . Only the absolute pressure is the state parameter of moist air. P gas + P H 2 O = 4 P gas = 4 - 0 . 4 = 3 . 6   atm As volume is doubled, P gas new   = 1 . 8   atm New Total Pressure = 1 . 8 + 0 . 4 = 2 . 2   atm

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