Points I, II and III in the following plot respectively correspond...

Points

I, II

and

III

in the following plot respectively correspond to (

{V}_{mp}:

most probable velocity)

Points I, II and III in the following plot respectively correspond to ( V _ mp : most probable velocity)

Options

A ${V}_{mp}$ of ${N}_{2}$ \left(300K\right); {V}_{mp} $of$ {H}_{2}\left(300K\right); {V}_{mp} $of$ {O}_{2}\left(400K\right);
B ${V}_{mp}$ of ${H}_{2}$ \left(300K\right); {V}_{mp} $of$ {N}_{2}\left(300K\right); {V}_{mp} $of$ {O}_{2}\left(400K\right);
C ${V}_{mp}$ of ${N}_{2}$ \left(300K\right); {V}_{mp} $of$ {O}_{2}\left(400K\right); {V}_{mp} $of$ {H}_{2}\left(300K\right);
D ${V}_{mp}$ of ${O}_{2}$ \left(400K\right); {V}_{mp} $of$ {N}_{2}\left(300K\right); {V}_{mp} $of$ {H}_{2}\left(300K\right);

Correct answer

C. ${V}_{mp}$ of ${N}_{2}$ \left(300K\right); {V}_{mp} $of$ {O}_{2}\left(400K\right); {V}_{mp} $of$ {H}_{2}\left(300K\right);

Step-by-step solution

${V}_{mp} = \sqrt{\dfrac{2RT}{M}} ∝ \sqrt{\dfrac{T}{M}}$

For ${N}_{2}$ at $300K,$ ${V}_{mp} ∝ \sqrt{\dfrac{T}{M}} ∝ \sqrt{\dfrac{300}{28}} = 3.2$

For ${O}_{2}$ at $300K,$ ${V}_{mp} ∝ \sqrt{\dfrac{T}{M}} ∝ \sqrt{\dfrac{400}{32}} = 3.53$

For ${H}_{2}$ at $300K,$ ${V}_{mp} ∝ \sqrt{\dfrac{T}{M}} ∝ \sqrt{\dfrac{300}{2}} = 12.24$

${V}_{mp}$ of ${N}_{2} < {U}_{mp}$ of ${O}_{2} < {U}_{mp}$ of ${H}_{2}$

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