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JEE Main 201910 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
10 April
Shift
Morning Shift
Subject
Chemistry
Chapter
States of Matter

JEE Main 2019 · 10 April · Morning Shift · Chemistry · States of Matter

Consider the following table: Gas a / (kPad m ^ 6 mo l ^ - 1 ) b /...

Consider the following table:
Gas a/(kPadm6mol−1)a / \left(kPad{m}^{6}mo{l}^{- 1}\right) b/(dm3mol−1)b / \left(d{m}^{3}mo{l}^{- 1}\right)
A 642.32642.32 0.051960.05196
B 155.21155.21 0.041360.04136
C 431.91431.91 0.051960.05196
D 155.21155.21 0.43820.4382

aa and bb are vander Waals constants. The correct statement about the gases is:

Options

  1. AGas CC will occupy more volume than gas AA ; gas BB will be lesser compressible than gas DD
  2. BGas CC will occupy lesser volume than gas AA ; gas BB will be lesser compressible than gas DD
  3. CGas CC will occupy more volume than gas AA ; gas BB will be more compressible than gas DD
  4. DGas CC will occupy lesser volume than gas AA ; gas BB will be more compressible than gas DD

Correct answer

C. Gas CC will occupy more volume than gas AA ; gas BB will be more compressible than gas DD

Step-by-step solution

* Gas A and C have same value of ‘b’ but different value of a so gas having higher value of a have more force of attraction so molecules will be more closer hence occupy less volume.
* Gas B and D have same value of ‘a’ but different value of b so gas having lesser value of b will be more compressible.
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