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JEE Main202628 January 2026Evening ShiftChemistryThermodynamics (C)Actual

The plot of ₁₀ ~K vs 1 ~T gives a straight line. The intercept and slope respectively are (where K is equilibrium constant).

Options

  1. AS ^ o 2 303 R ,- H ^ o 2 303 R
  2. B- S ^ R 2 303 , H ^ R 2 303
  3. C2 303 R H ^ o , 2 303 R ~S ^ o
  4. D- H ^ o 2 303 R , ~S ^ o 2 303 R

Correct answer

A. S ^ o 2 303 R ,- H ^ o 2 303 R

Step-by-step solution

The relationship between the standard Gibbs free energy change and the equilibrium constant is given by G^o = -RT K . We also know that G^o = H^o - T S^o . Equating the two expressions: -RT K = H^o - T S^o . Dividing by -RT , we get: K = - H^o RT + S^o R . To convert natural log to base 10, use K = 2.303 ₁₀ K : 2.303 ₁₀ K = - H^o RT + S^o R . Dividing by 2.303 : ₁₀ K = - H^o 2.303RT + S^o 2.303R . Rearranging in the form of a straight line equation y = mx + c where y = ₁₀ K and x = 1 T : ₁₀ K = ( - H^o 2.303R ) 1 T

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