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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2026 · 24 January · Morning Shift · Chemistry · Thermodynamics (C)

Match the List-I with List-II ( List-I Isothermal process for ideal...

Match the List-I with List-II
(
List-IIsothermal process
for ideal gas systemList-IIWork done (V_f \gt V_i)
A.Reversible expansionI.w = 0
B.Free expansionII.w = -nRT \ln VfVi\dfrac{V_f}{V_i}
C.Irreversible expansionIII.w = -p_{ex}(V_f - V_i)
D.Irreversible compressionIV.w = -p_{ex}(V_i - V_f)
)
Choose the correct answer from the options given below:

Options

  1. AA-I, B-III, C-II, D-IV
  2. BA-II, B-I, C-III, D-IV
  3. CA-IV, B-I, C-III, D-II
  4. DA-IV, B-II, C-III, D-I

Correct answer

B. A-II, B-I, C-III, D-IV

Step-by-step solution

Matching isothermal processes with work expressions:
A. Reversible expansion: In a reversible isothermal expansion from ViV_i to VfV_f (where Vf>ViV_f > V_i), the gas does work against external pressure equal to the surroundings. The work is w=nRTln⁡VfViw = nRT \ln \frac{V_f}{V_i}, matching II.
B. Free expansion: The gas expands into a vacuum with no external pressure opposition. No work is done: w=0w = 0, matching I.
C. Irreversible expansion: Isothermal expansion from ViV_i to VfV_f against constant external pressure pexp_{ex}. Work done is w=−pex(Vf−Vi)w = -p_{ex}(V_f - V_i), matching III.
D. Irreversible compression: Isothermal compression from ViV_i to VfV_f (where Vf<ViV_f < V_i) against constant external pressure. Work is w=−pex(Vi−Vf)w = -p_{ex}(V_i - V_f), matching IV.

The correct pairings are A-II, B-I, C-III, D-IV.
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