JEE Main20254 Apr 2025Evening ShiftChemistryThermodynamics (C)Actual
Consider the given data : (a) HCl ( g )+10 H ₂ O ( l ) HCl .10 H ₂ O H =-69.01 ~kJ ~mol ⁻¹ (b) HCl ( g )+40 H ₂ O ( l ) HCl .40 H ₂ O H =-72.79 ~kJ ~mol ⁻¹ Choose the correct statement :
Options
- ADissolution of gas in water is an endothermic process
- BThe heat of solution depends on the amount of solvent.
- CThe heat of dilution for the HCl ( HCl 10 H ₂ O . to . HCl .40 H ₂ O ) is 3.78 ~kJ ~mol ⁻¹ .
- DThe heat of formation of HCl solution is represented by both (a) and (b)
Correct answer
B. The heat of solution depends on the amount of solvent.
Step-by-step solution
From the given information H is negative so it means dissolution of gas HCl ( g ) is exothermic. HCl ( g )+10 H ₂ O ( l ) HCl .10 H ₂ O ...(1) H ₁=-69.01 ~kJ ~mol HCl ( g )+40 H ₂ O ( l ) HCl .40 H ₂ O ...(2) H ₂=-72.79 ~kJ ~mol Hence heat of solution depends upon amount of solvent By equation..(2) - equation HCl .10 H ₂ O +30 H ₂ O ( ) HCl 40 H ₂ O So Heat of dilution =-72.79-(-69.01) =-3.78 ~kJ ~mol Hence option (3) is incorrect. For heat of formation reactant should be in elemental form hence option (4) is incor