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JEE Main 202529 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
29 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2025 · 29 January · Evening Shift · Chemistry · Thermodynamics (C)

If C (diamond ) arrow C (graphite )+X kJ mol^ -1 C( diamond...

If C\quad C (diamond )→C) \rightarrow C (graphite )+XkJmol−1)+\mathrm{X} \mathrm{kJ} \mathrm{mol}^{-1} C(\mathrm{C}( diamond )+O2( g)→CO2( g)+YkJmol−1)+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Y} \mathrm{kJ} \mathrm{mol}^{-1} C (graphite) +O2( g)→CO2( g)+ZkJmol−1+\mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+\mathrm{Z} \mathrm{kJ} \mathrm{mol}^{-1} at constant temperature. ThenIf C (diamond ) arrow C (graphite )+X kJ mol^ -1 C( diamond )+O_2(~g) arrow CO_2(~g)+Y kJ mol^ -1 C (graphite) +O_2(~g)

Options

  1. AX=-Y+Z
  2. B-X=Y+Z
  3. CX=Y+Z
  4. DX=Y-Z

Correct answer

D. X=Y-Z

Step-by-step solution

If C (diamond ) arrow C (graphite )+X kJ mol^ -1 C( diamond )+O_2(~g) arrow CO_2(~g)+Y kJ mol^ -1 C (graphite) +O_2(~g)
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