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500 J of energy is transferred as heat to 0.5 mol of Argon gas at 298 K and 1.00 atm. The final temperature and the change in internal energy respectively are: Given : ( R =8.3 ~J ~K ⁻¹ ~mol ⁻¹ )

Options

  1. A378 K and 500 J
  2. B368 K and 500 J
  3. C348 K and 300 J
  4. D378 K and 300 J

Correct answer

C. 348 K and 300 J

Step-by-step solution

aligned & q _ p = n c _ p T & 500=0.5 5 2 8.3 ( ~T _ f -298 ) & T _ f 346.2 ~K & H U = C _ p C _ v = ( 5 3 ) & U = 3 5 500=300 ~J aligned

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