Consider the following data : Heat of formation of CO ₂( ~g )=-393.5 ~kJ ~mol ⁻¹ Heat of formation of H ₂ O ( l )=-286.0 ~kJ ~mol ⁻¹ Heat of combustion of benzene =-3267.0 ~kJ ~mol ⁻¹ The heat of formation of benzene is _ kJ mol ⁻¹ . (Nearest integer)

Step-by-step solution

aligned & H _ f [ CO ₂( ~g ) ]=-393.5 ~kJ / mole & H _ f [ H ₂ O ( ) ]=-286.0 ~kJ / mole & H _ c [ C ₆ H ₆ ]=-3267.0 ~kJ / mole & H _ f C ₆ H ₆=(?) & C ₆ H ₆+ 15 2 O ₂( ~g ) 6 CO ₂( ~g )+3 H ₂ O ( ) & H _ R = H _ C = H _ f ( P )- H _ f ( R ) & -3267=6 (-393.5)+3(-286)- H _ f ( C ₆ H ₆ ) & H _ f ( C ₆ H ₆ )=48 ~kJ / mole aligned