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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2025 · 28 January · Evening Shift · Chemistry · Thermodynamics (C)

An ideal gas undergoes a cyclic transformation starting from the...

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing
An ideal gas undergoes a cyclic transformation starting from the point AA and coming back to the same point by tracing the path A→B→C→D→A\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D} \rightarrow \mathrm{A} as shown in the three cases above. Choose the correct option regarding ΔU\Delta \mathrm{U} :

Options

  1. AΔU(\Delta \mathrm{U}( Case-I )=ΔU()=\Delta \mathrm{U}( Case-II )=ΔU()=\Delta \mathrm{U}( Case-III ))
  2. BΔU(\Delta \mathrm{U}( Case-I )>ΔU()\gt\Delta \mathrm{U}( Case-III )>ΔU()\gt\Delta \mathrm{U}( Case-II ))
  3. CΔU(\Delta \mathrm{U}( Case-III )>ΔU()\gt\Delta \mathrm{U}( Case-II )>ΔU()\gt\Delta \mathrm{U}( Case-I ))
  4. DΔU(\Delta \mathrm{U}( Case-I )>ΔU()\gt\Delta \mathrm{U}( Case-II )>ΔU()\gt\Delta \mathrm{U}( Case-III ))

Correct answer

A. ΔU(\Delta \mathrm{U}( Case-I )=ΔU()=\Delta \mathrm{U}( Case-II )=ΔU()=\Delta \mathrm{U}( Case-III ))

Step-by-step solution

As internal energy ' UU ' is a state function, its cyclic integral must be zero in a cyclic process ∴ΔU case (I)=ΔU case ( II )=ΔU case ( III )\therefore \Delta U \text{ case }(I)=\Delta U \text{ case }(\text{ II })=\Delta U \text{ case }(\text{ III })
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