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For a certain thermochemical reaction M → N at T = 400 K , ΔH o = 77 . 2 kJ mol - 1 , ΔS o = 122 JK - 1 , log equilibrium constant ( logK ) is - _____ × 10 - 1 .

Correct answer

0

Step-by-step solution

Given, T = 400 K , ΔH o = 77 . 2 kJ mol - 1 , ΔS o = 122 JK - 1 ΔG o = ΔH o - TΔS o = 77 . 2 × 10 3 - 400 × 122 = 28400 J ΔG ° = - 2 . 303 R T log K Where K is the equilibrium constant. By putting the values in above equation, ⇒ 28400 = - 2 . 303 × 8 . 314 × 400 × log K ⇒ log K = - 3 . 708 = - 37 . 08 × 10 - 1

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