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JEE Main 202315 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
15 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2023 · 15 April · Morning Shift · Chemistry · Thermodynamics (C)

30 . 4kJ of heat is required to melt one mole of sodium chloride...

30.4kJ30 . 4kJ of heat is required to melt one mole of sodium chloride and the entropy change at the melting point is 28.4JK–1mol–128 . 4J{K}^{– 1}{mol}^{– 1} at 1atm1atm. The melting point of sodium chloride is _______ KK (Nearest Integer)

Correct answer

0

Step-by-step solution

The equilibrium process can be written as follows,

NaCl(s)⇌NaCl(l)ΔS=ΔHTempT=ΔHΔS=30.4×10328.4=1070.4K\begin{array}{ll}NaCl\left(s\right)⇌NaCl\left(l\right) \\ \Delta S = \dfrac{\Delta H}{Temp} \\ T = \dfrac{\Delta H}{\Delta S} \\ = \dfrac{30 .4 \times {10}^{3}}{28 .4} \\ = 1070 .4 K\end{array}

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