In a one-litre flask, 6 moles of A undergoes the reaction A ( g ) ⇌ P ( g ) . The progress of product formation at two temperatures (in Kelvin), T 1 and T 2 , is shown in the figure: If T 1 = 2 T 2 and ΔG 2 o - ΔG 1 o = RT 2 lnx , then the value of x is [ ΔG 1 o and ΔG 2 o are standard Gibb's free energy change for the reaction at temperatures T 1 and T 2 , respectively.]

Step-by-step solution

The equilibrium moles can be calculated as follows,                                                           A g ⇌ P g initial                                             6                         &