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JEE Main202312 Apr 2023Morning ShiftChemistryThermodynamics (C)Actual

One mole of an ideal gas at 350 K is in a 2 . 0 L vessel of thermally conducting walls, which are in contact with the surroundings. It undergoes isothermal reversible expansion from 2 . 0 L to 3 . 0 L against a constant pressure of 4 atm . The change in entropy of the surroundings ( ∆ S ) is _____ J K – 1 (Nearest integer) Given: R = 8 . 314 J K - 1 mol - 1 .

Correct answer

0

Step-by-step solution

The first law of thermodynamics for isothermal process Q = - W The W for isothermal reversible process is W = - n R T ln V 2 V 1 ∆ S = Q T ∆ S surrounding = - n R ln V 2 V 1 = - 1 × 8 . 314 × 2 . 303 × log 3 2 = - 3 . 37   JK - 1 ≃ - 3   JK - 1 The given process is mentioned as isothermal reversible process hence the ∆ S surrounding is calculated.

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