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JEE Main 202312 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
12 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2023 · 12 April · Morning Shift · Chemistry · Thermodynamics (C)

One mole of an ideal gas at 350K is in a 2 . 0L vessel of thermally...

One mole of an ideal gas at 350K350K is in a 2.0L2 . 0L vessel of thermally conducting walls, which are in contact with the surroundings. It undergoes isothermal reversible expansion from 2.0L2 . 0L to 3.0L3 . 0L against a constant pressure of 4atm4atm. The change in entropy of the surroundings (∆S)( ∆ S ) is _____ JK–1J{K}^{– 1} (Nearest integer)

Given: R=8.314JK−1mol−1R = 8 . 314J{K}^{- 1}{mol}^{- 1}.

Correct answer

0

Step-by-step solution

The first law of thermodynamics for isothermal process Q=−WQ = - W

The WW for isothermal reversible process is

W=−nRTlnV2V1W = - nRTln\dfrac{{V}_{2}}{{V}_{1}}

∆S=QT∆ S = \dfrac{Q}{T}

∆Ssurrounding=−nRlnV2V1∆ {S}_{surrounding} = - nRln\dfrac{{V}_{2}}{{V}_{1}}

=−1×8.314×2.303×log32= - 1 \times 8 . 314 \times 2 . 303 \times log\dfrac{3}{2}

=−3.37JK−1= - 3 . 37{JK}^{- 1}

≃−3JK−1≃ - 3{JK}^{- 1}

The given process is mentioned as isothermal reversible process hence the ∆Ssurrounding∆ {S}_{surrounding} is calculated.

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