JEE Main202310 Apr 2023Morning ShiftChemistryThermodynamics (C)Actual
FeO 4 2 - ⟶ + 2 . 2 V Fe 3 + ⟶ + 0 . 70 V Fe 2 + ⟶ - 0 . 45 V Fe 0 E FeO 4 2 - / Fe 2 + θ is x × 10 - 3 V . The value of x is _______
Correct answer
0
Step-by-step solution
The relation between ∆ G o and E cell o is ∆ G o = - nFE cell o FeO 4 2 - ⟶ + 2 . 2   V Fe 3 +   ΔG 1 o = - 6 . 6   F (3 electrons are involved) Fe 3 + ⟶ + 0 . 70   V Fe 2 + ΔG 2 o = - 0 . 7   F (one electron is involved) Hence, for FeO 4 2 - ⟶ Fe 2 + ΔG 3 o = - 7 . 3   F = - nFE cell o (Four electrons are involved) E FeO 4 2 - / Fe + 2 0 = - 7 . 3   F - 4   F = 1 . 825 ,   n = 4 = 1825 × 10 - 3   V n = Electron e