JEE Main20238 Apr 2023Morning ShiftChemistryThermodynamics (C)Actual
When a 60 W electric heater is immersed in a gas for 100 s in a constant volume container with adiabatic walls, the temperature of the gas rises by 5 ° C . The heat capacity of the given gas is JK - 1 (Nearest integer)
Correct answer
0
Step-by-step solution
 Heat capacity  =  Heat absorbed   change in temperature  1 Watt = 1 Joule per second Hence, heat absorbed = 60 × 100 J Change in temperature = 5 ° C Heat capacity = 60 × 100   J 5 = 1200 JK - 1