JEE Main202228 Jul 2022Evening ShiftChemistryThermodynamics (C)Actual
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R Assertion A : The reduction of a metal oxide is easier if the metal formed is in liquid state than solid state. Reason R : The value of ΔG Θ becomes more on negative side as entropy is higher in liquid state than solid state. In the light of the above statements. Choose the most appropriate answer from the o
Options
- ABoth A and R are correct and R is the correct explanation of A
- BBoth A and R are correct but R is NOT the correct explanation of A
- CA is correct but R is not correct
- DA is not correct but R is correct
Correct answer
A. Both A and R are correct and R is the correct explanation of A
Step-by-step solution
The entropy is higher if the metal is in liquid state than when it is in solid state. The value of entropy change ( ∆ S ) of the reduction process is more on positive side when the metal formed is in liquid state and the metal oxide being reduced is in solid state. Thus the value of ∆ f G becomes more on negative side and the reduction becomes easier. ΔG = ΔH - TΔS ∵ Entropy of liquid is more than solid ∴ on melting the entropy increases and ΔG becomes more negative and h