When 600   mL of 0 . 2 M   HNO 3 is mixed with 400   mL of 0 . 1 M   NaOH solution in a flask, the rise in temperature of the flask is_____ × 10 - 2   ° C (Enthalpy of neutralisation = 57   kJ   mol - 1 and Specific heat of water = 4 . 2 JK - 1   g - 1 ) (Neglect heat capacity of flask)

Step-by-step solution

Number of moles of given acid and base are HNO 3   =   600 1000 × 0 . 2   M =   0 . 12   moles   NaOH   =   400 1000 × 0 . 1   M   =   0 . 04   moles Now neutralisation reaction between them will be HNO 3         +     NaOH     →     NaNO 3 + H 2 O 0 . 12   mole     0 . 04   mole 0 . 08   mole       0   mole           &#16