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JEE Main 202228 JulyMorning Shift
Exam
JEE Main
Year
2022
Date
28 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2022 · 28 July · Morning Shift · Chemistry · Thermodynamics (C)

Which of the following relation is not correct?

Which of the following relation is not correct?

Options

  1. AΔH=ΔU−PΔV\Delta H = \Delta U - P \Delta V
  2. BΔU=q+W\Delta U = q + W
  3. CΔSsys+ΔSsurr≥0{\Delta S}_{sys} + {\Delta S}_{surr} \ge 0
  4. DΔG=ΔH−TΔS\Delta G = \Delta H - T \Delta S

Correct answer

A. ΔH=ΔU−PΔV\Delta H = \Delta U - P \Delta V

Step-by-step solution

Enthalpy, in a thermodynamic system, is the measure of its energy which is equal to the sum of the internal energy and the product of its pressure and volume.

H=U+PVH = U + PV (By definition)

ΔH=ΔU+Δ(PV)orΔH=ΔU+VΔP+PΔV\Delta H = \Delta U + \Delta\left(PV\right)or\Delta H = \Delta U + V \Delta P + P \Delta V

at constant pressure

ΔH=ΔU+PΔV\Delta H = \Delta U + P \Delta V So, option A is incorrect.

ΔU=q+W\Delta U = q + W First law of thermodynamics.

ΔSsys+ΔSsurr≥0orΔSUniverse≥0{\Delta S}_{sys} + {\Delta S}_{surr} \ge 0or{\Delta S}_{Universe} \ge 0 A form of second law of thermodynamics.

ΔG=ΔH−TΔS\Delta G = \Delta H - T \Delta S Second law of thermodynamics.

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