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A gas ( Molar mass = 280   g   mol - 1 ) was burnt in excess O 2 in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298 . 0   K to 298 . 45   K . If the heat capacity of calorimeter is 2 . 5   kJ   K - 1 and enthalpy of combustion of gas is 9   kJ   mol - 1 then amount of gas burnt is____ g .

Correct answer

0

Step-by-step solution

Let x   g is burnt Moles = x 280 heat released by x 280   mole = 2 . 5 × 0 . 45   kJ heat released by 1 mole = 2 . 5 × 0 . 45 × 280 x kJ ΔH = ΔU + ΔngRT ΔH ≃ ΔU 9 = 2 . 5 × 280 × 0 . 45 x x = 35   g

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