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JEE Main 202227 JulyEvening Shift
Exam
JEE Main
Year
2022
Date
27 July
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2022 · 27 July · Evening Shift · Chemistry · Thermodynamics (C)

A gas ( Molar mass = 280g mol ^ - 1 ) was burnt in excess O _ 2 in...

A gas ( Molar mass =280gmol−1= 280g{mol}^{- 1}) was burnt in excess O2{O}_{2} in a constant volume calorimeter and during combustion the temperature of calorimeter increased from 298.0K298 . 0K to 298.45K298 . 45K. If the heat capacity of calorimeter is 2.5kJK−12 . 5kJ{K}^{- 1} and enthalpy of combustion of gas is 9kJmol−19kJ{mol}^{- 1} then amount of gas burnt is____gg.

Correct answer

0

Step-by-step solution

Let xgxg is burnt

Moles=x280= \dfrac{x}{280} heat released by x280mole=2.5×0.45kJ\dfrac{x}{280}mole = 2 . 5 \times 0 . 45kJ heat released by 11 mole =2.5×0.45×280xkJ= \dfrac{2 . 5 \times 0 . 45 \times 280}{x}kJ

ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta ngRT

ΔH≃ΔU\Delta H ≃ \Delta U

9=2.5×280×0.45x9 = \dfrac{2 . 5 \times 280 \times 0 . 45}{x}

x=35gx = 35g

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