When 5 moles of He gas expand isothermally and reversibly at 300K from 10 litre to 20 litre, the magnitude of the maximum work obtained is J . [nearest integer ] (Given : R = 8 . 3J K ^ - 1 mol ^ - 1 and 2 = 0 . 3010 )

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Work done in isothermal reversible process is calculated by the equation

$W = - 2 . 303nRTlog\left(\dfrac{{V}_{2}}{{V}_{1}}\right)n = NumberofmolesT = Temperature = 300K{V}_{2} = Finalvolume = 20litres{V}_{1} = Initialvolume = 10litres$

W $= - 2 . 303 \times 5 \times 8 . 3 \times 300\log \left(\dfrac{20}{10}\right)$

$= - 8630 . 38J$

When 5 moles of He gas expand isothermally and reversibly at 300K...

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