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JEE Main 202227 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
27 June
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2022 · 27 June · Morning Shift · Chemistry · Thermodynamics (C)

Match List - I with List - II. List-I List-II (A) Spontaneous...

Match List - I with List - II.

List-I List-II
(A)\left(A\right) Spontaneous process \left(I\right)</td><td></td> <td>\Delta H < 0</td></tr><tr><td>(B)</td> </tr> <tr> <td>\left(B\right) Process with ΔP=0,ΔT=0\Delta P = 0, \Delta T = 0 \left(II\right)</td><td></td> <td>{\Delta G}_{T, P} < 0</td></tr><tr><td>(C)</td> </tr> <tr> <td>\left(C\right) ΔHreaction{\Delta H}_{reaction} \left(III\right)</td><td>Isothermalandisobaricprocess</td></tr><tr><td>(D)</td> <td>Isothermal and isobaric process</td> </tr> <tr> <td>\left(D\right) Exothermic Process \left(IV\right) [Bond energies of molecules in reactants] -
[Bond energies of product molecules]

Choose the correct answer from the options given below

Options

  1. A(A)−(III),(B)−(II),(C)−(IV),(D)−(I)\left(A\right) - \left(III\right), \left(B\right) - \left(II\right), \left(C\right) - \left(IV\right), \left(D\right) - \left(I\right)
  2. B(A)−(II),(B)−(III),(C)−(IV),(D)−(I)\left(A\right) - \left(II\right), \left(B\right) - \left(III\right), \left(C\right) - \left(IV\right), \left(D\right) - \left(I\right)
  3. C(A)−(II),(B)−(III),(C)−(I),(D)−(IV)\left(A\right) - \left(II\right), \left(B\right) - \left(III\right), \left(C\right) - \left(I\right), \left(D\right) - \left(IV\right)
  4. D(A)−(II),(B)−(I),(C)−(III),(D)−(IV)\left(A\right) - \left(II\right), \left(B\right) - \left(I\right), \left(C\right) - \left(III\right), \left(D\right) - \left(IV\right)

Correct answer

B. (A)−(II),(B)−(III),(C)−(IV),(D)−(I)\left(A\right) - \left(II\right), \left(B\right) - \left(III\right), \left(C\right) - \left(IV\right), \left(D\right) - \left(I\right)

Step-by-step solution

(A) For a spontaneous process ΔGT,P<0{\Delta G}_{T, P} < 0

(B) ΔP=0→\Delta P = 0 \to Isobaric process(pressure is constant in this process) ΔT=0→\Delta T = 0 \to Isothermal process(Temperature is constant in this process).

(C) ΔHreaction={\Delta H}_{reaction} =(ΣΣ Bond energies of reactants)-
(ΣΣbond energies of products)

(D) ΔH<0\Delta H < 0 is for exothermic reaction

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