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For complete combustion of methanol CH 3 OH l + 3 2 O 2 g → CO 2 g + 2 H 2 O l the amount of heat produced as measured by bomb calorimeter is 726   kJ   mol - 1 at 27   ° C . The enthalpy of combustion for the reaction is - x   kJ   mol - 1 , where x is integer) (Given : R = 8 . 3 JK - 1   mol - 1 )

Correct answer

727

Step-by-step solution

CH 3 OH l + 3 2 O 2 g → CO 2 g + 2 H 2 O l . For chemical reaction : ΔH = ΔU + Δn g RT Δ H = - 726 + - 1 2 8 . 314 × 10 - 3 × 300 = - 727 . 245 KJ / mole ∴   x = 727

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