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JEE Main 202226 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2022 · 26 June · Evening Shift · Chemistry · Thermodynamics (C)

40 % of HI undergoes decomposition to H _ 2 and I _ 2 at 300K . Δ G...

40 % of HIundergoesdecompositiontoundergoes decomposition to{H}_{2} and {I}_{2}atat300K . {\Delta G}^{Θ}for this decompostion reaction at one atmopsphere pressure is____{Jmol}^{- 1}−[nearestinteger]</p><p>(UseR=8.31JK−1mol−1;log⁡2=0.3010,ln⁡10=2.3,log⁡3=0.477)-[nearest integer]</p><p>\left(UseR = 8 . 31{JK}^{- 1}{mol}^{- 1}; \log 2 = 0 . 3010, \ln 10 = 2 . 3, \log 3 = 0 . 477\right)

Correct answer

0

Step-by-step solution

HI (g)⇌12H\left(g\right) ⇌ \dfrac{1}{2}{H}_{2}(g)\left(g\right) + 12\dfrac{1}{2}{I}_{2}\left(g\right)</p><tableborder="1"cellpadding="1"cellspacing="1"style="width:200px;"><tbody><tr><td>Initialmoles</p><table border="1" cellpadding="1" cellspacing="1" style="width: 200px;"> <tbody> <tr> <td>Initial moles 11 00 00 moles at equilibrium</td><tdstyle="text−align:center;">(1−0.4)</td> <td style="text-align: center;">\left(1 - 0 . 4\right) 0.20 . 2 0.20 . 2

KP=(0.2)12×(0.2)12(0.6){K}_{P} = \dfrac{{\left(0 . 2\right)}^{\dfrac{1}{2}} \times {\left(0 . 2\right)}^{\dfrac{1}{2}}}{\left(0 . 6\right)}

KP=0.20.6=13</p><p>{K}_{P} = \dfrac{0 . 2}{0 . 6} = \dfrac{1}{3}</p><p>\Delta G ° = - 2 . 3{RTlogK}_{P}</p><p></p><p>= - 2 . 3 \times 8 . 31 \times 300log13\dfrac{1}{3}

=2375Jmol−12375{Jmol}^{- 1}

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