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JEE Main 202120 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2021 · 20 July · Morning Shift · Chemistry · Thermodynamics (C)

An average person needs about 10000kJ energy per day. The amount of...

An average person needs about 10000kJ10000kJ energy per day. The amount of glucose (molar mass =180.0gmol−1= 180 . 0g{mol}^{- 1}) needed to meet this energy requirement is ______g.g .
(Use : ΔCH{\Delta}_{C}H (glucose)=−2700kJmol−1= - 2700kJ{mol}^{- 1})

Correct answer

0

Step-by-step solution

11 mole glucose give 2700kJ2700kJ energy so mole of glucose needed for 104kJ{10}^{4}kJ energy
=100002700=3.7037moles= \dfrac{10000}{2700} = 3 . 7037moles
wt. of glucose =3.7037×180= 3 . 7037 \times 180

=666.666= 666 . 666
≈667gm\approx 667gm

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