The gas phase reaction 2 A g ⇌ A 2 g at 400 K has Δ G o = + 25 . 2 kJ mol - 1 . The equilibrium constant K C for this reaction is ___ × 10 - 2 . (Round off to the Nearest integer) Use : R = 8 . 3 J mol - 1 K - 1 , ln 10 = 2 . 3 log 10 2 = 0 . 30 , 1 atm = 1 bar antilog ( - 0 . 3 ) = 0 . 501

Step-by-step solution

Using formula Δ r G 0 = - RTlnK p 25200 = - 2 . 3 × 8 . 3 × 400 log K p K p = 10 - 3 . 3 = 10 - 3 × 0 . 501 = 5 . 01 × 10 - 4 Bar - 1 = 5 . 01 × 10 - 9   Pa - 1 = K C 8 . 3 × 400 K C = 1 . 66 × 10 - 5   m 3 / mole = 1 . 66 × 10 - 2   L / mol = 2 Gibbs free energy can be visualized as the amount of useful energy present in a thermodynamic system that can be utilized to perform some useful work.