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JEE Main 202126 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Morning Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2021 · 26 February · Morning Shift · Chemistry · Thermodynamics (C)

For a chemical reaction A + B = C + D ( Δ _ r H ^ Θ = 80kJ mol ^ -...

For a chemical reaction A+B=C+DA + B = C + D\left({\Delta}_{r}{H}^{Θ} = 80kJ{mol}^{- 1}\right)theentropychangeΔrSΘthe entropy change{\Delta}_{r}{S}^{Θ} depends on the temperature TT (in KK)asΔrSΘ=2T(JK−1mol−1)as {\Delta}_{r}{S}^{Θ} = 2T\left({JK}^{- 1}{mol}^{- 1}\right). Minimum temperature at which it will become spontaneous is KK. (Integer)

Correct answer

200

Step-by-step solution

ΔG°=ΔH°−T×ΔS°\Delta G ° = \Delta H ° - T \times \Delta S °

ΔG°=ΔH°−T×(2T)\Delta G ° = \Delta H ° - T \times \left(2T\right)

T=200KT = 200K

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