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JEE Main 202126 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
26 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Thermodynamics (C)

JEE Main 2021 · 26 February · Evening Shift · Chemistry · Thermodynamics (C)

The average S - F bond energy in kJ mol ^ - 1 of SF _ 6 is _....

The average S−FS - F bond energy in kJmol−1kJ{mol}^{- 1} of SF6{SF}_{6} is _. (Rounded off to the nearest integer)

[Given : The values of standard enthalpy of formation of SF6(g),S(g){SF}_{6}\left(g\right), S\left(g\right) and F(g)F\left(g\right) are −1100,275- 1100, 275 and 80kJmol−180kJ{mol}^{- 1} respectively.]

Correct answer

0

Step-by-step solution

SF6(g)→S(g)+6F(g){SF}_{6}\left(g\right) \to S\left(g\right) + 6F\left(g\right)

If ∈\in- bond enthalpy

ΔrH=6×ϵS−F{\Delta}_{r}H = 6 \times {ϵ}_{S - F}

=ΔfH(S,g)+6×ΔfH(F,g)−ΔfH(SF6,g)= {\Delta}_{f}H\left(S, g\right) + 6 \times {\Delta}_{f}H\left(F, g\right) - {\Delta}_{f}H\left({SF}_{6}, g\right)

=275+6×80−(−1100)= 275 + 6 \times 80 - \left(- 1100\right)

=1855kJ= 1855kJ

ϵS−F=18556=309.16kJmol−1{ϵ}_{S - F} = \dfrac{1855}{6} = 309 . 16kJ{mol}^{- 1}

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