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Lattice enthalpy and enthalpy of solution of NaCl are 788 kJmol - 1 and 4 k J m o l - 1 , respectively. The hydration enthalpy of N a C l is:

Options

  1. A- 780 kJmol - 1
  2. B780 kJmol - 1
  3. C- 784 kJmol - 1
  4. D784 kJmol - 1

Correct answer

C. - 784 kJmol - 1

Step-by-step solution

Enthalpy of solution= Lattice enthalpy + enthalpy of hydration 4 = 788 +   ∆ H hydration ⇒ ∆ H hydration = - 784   KJ / mol

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