JEE Main 202324 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Main 2023 · 24 January · Morning Shift · Mathematics · Definite Integration
The value of (8)/(π) ∫ _ 0 ^ (π)/(2) ( x ) ^ 2023 ( x) ^ 2023 + (...
The value of \dfrac{8}{\pi}{∫}_{0}^{\dfrac{\pi}{2}}\dfrac{{\left(\text{ \cos x }\right)}^{2023}}{{\left(\sin x\right)}^{2023} + {\left(\cos x\right)}^{2023}}dx is ______.
Correct answer
0
Step-by-step solution
Let
I = \dfrac{8}{\pi}{∫}_{0}^{\dfrac{\pi}{2}}\dfrac{{\left(\cos x\right)}^{2023}}{{\left(\sin x\right)}^{2023} + {\left(\cos x\right)}^{2023}}dx . . . \left(1\right){∫}_{0}^{a}f ( x ) dx = {∫}_{0}^{a}f ( a - x ) dxI = \dfrac{8}{\pi}{∫}_{0}^{\dfrac{\pi}{2}}\dfrac{{\left(\sin x\right)}^{2023}}{{\left(\sin x\right)}^{2023} + {\left(\cos x\right)}^{2023}}dx . . . \left(2\right)
Adding \left(1\right), we get