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JEE Main 20254 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Ellipse

JEE Main 2025 · 4 April · Morning Shift · Mathematics · Ellipse

The length of the latus-rectum of the ellipse, whose foci are (2,5)...

The length of the latus-rectum of the ellipse, whose foci are (2,5)(2,5) and (2,−3)(2,-3) and eccentricity is 45\frac{4}{5}, is

Options

  1. A65\frac{6}{5}
  2. B503\frac{50}{3}
  3. C103\frac{10}{3}
  4. D185\frac{18}{5}

Correct answer

D. 185\frac{18}{5}

Step-by-step solution

2be=8be=4\begin{aligned} & 2 \mathrm{be}=8 \\ & \mathrm{be}=4\end{aligned}b(45)=4⇒b=5∵c2=b2−a216=25−a2⇒a=3 L.R. =2a2b=185\begin{aligned} & \mathrm{b}\left(\frac{4}{5}\right)=4 \Rightarrow \mathrm{ b}=5 \\ & \because \mathrm{c}^2=\mathrm{b}^2-\mathrm{a}^2 \\ & 16=25-\mathrm{a}^2 \Rightarrow \mathrm{a}=3 \\ & \text{ L.R. }=\frac{2 \mathrm{a}^2}{\mathrm{ b}}=\frac{18}{5}\end{aligned}$
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