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JEE Main202523 Jan 2025Evening ShiftMathematicsEllipseActual

The length of the chord of the ellipse x^2 4 + y^2 2 =1 , whose mid-point is (1, 1 2 ) , is :

Options

  1. A5 3 15
  2. B1 3 15
  3. C2 3 15
  4. D15

Correct answer

C. 2 3 15

Step-by-step solution

aligned & T=S₁ & x 1 4 + y 4 = 1 4 + 1 8 & 2 x+2 y=3 & x^2 4 + ( 3-2 x 2 )^2 2 =1 & x= 12 120 12 y= 1 2 120 12 aligned So length of chord = 2 15 3

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