JEE Main2013MathematicsEllipseActual
Equation of the line passing through the points of intersection of the parabola x^2=8 y and the ellipse x^2 3 +y^2=1 is :
Options
- Ay-3=0
- By+3=0
- C3 y+1=0
- D3 y-1=0
Correct answer
D. 3 y-1=0
Step-by-step solution
x^2=8 y x^2 3 +y^2=1 From (i) and (ii), 8 y 3 +y^2=1 y=-3, 1 3 When y=-3 , then x^2=-24 , which is not possible. When y= 1 3 , then x= 2 6 3 Point of intersection are ( 2 6 3 , 1 3 ) and (- 2 6 3 , 1 3 ) Required equation of the line, y- 1 3 =0 3 y-1=0