JEE Main2011MathematicsEllipseActual
Equation of the ellipse whose axes are the axes of coordinates and which passes through the point (-3,1) and has eccentricity 2 5 is
Options
- A5 x^2+3 y^2-48=0
- B3 x^2+5 y^2-15=0
- C5 x^2+3 y^2-32=0
- D3 x^2+5 y^2-32=0
Correct answer
D. 3 x^2+5 y^2-32=0
Step-by-step solution
aligned & b ^2= a ^2 (1- e ^2 )= a ^2 (1- 2 5 )= a ^2 3 5 = 3 a ^2 5 & x ^2 a ^2 + y ^2 ~b ^2 =1 9 a ^2 + 5 3 a ^2 =1 & a ^2= 32 3 & ~b ^2= 32 5 aligned Required equation of ellipse 3 x^2+5 y^2-32=0