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The ellipse x^2+4 y^2=4 is inscribed in a rectangle aligned with the coordinate axes, which in turn in inscribed in another ellipse that passes through the point (4,0) . Then the equation of the ellipse is

Options

  1. Ax^2+16 y^2=16
  2. Bx^2+12 y^2=16
  3. C4 x^2+48 y^2=48
  4. D4 x ^2+64 y ^2=48

Correct answer

B. x^2+12 y^2=16

Step-by-step solution

x^2+4 y^2=4 x^2 4 + y^2 1 =1 a=2, b=1 P=(2,1) Required Ellipse is x^2 a^2 + y^2 b^2 =1 x^2 4^2 + y^2 b^2 =1(2,1) lies on it aligned & 4 16 + 1 b^2 =1 1 b^2 =1- 1 4 = 3 4 b^2= 4 3 & x^2 16 + y^2 ( 4 3 ) =1 x^2 16 + 3 y^2 4 =1 x^2+12 y^2=16 aligned

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