JEE Main2004MathematicsEllipseActual
The eccentricity of an ellipse, with its centre at the origin, is 1 2 . If one of the directrices is x= 4 , then the equation of the ellipse is
Options
- A3 x^2+4 y^2=1
- B3 x^2+4 y^2=12
- C4 x^2+3 y^2=12
- D4 x^2+3 y^2=1
Correct answer
B. 3 x^2+4 y^2=12
Step-by-step solution
Equation of directrix is x=a / e=4 a=2 b^2=a^2 (1-e^2 ) b^2=3 Hence equation of ellipse is 3 x^2+4 y^2=12