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JEE Main20245 Apr 2024Evening ShiftMathematicsLimitsActual

Let a >0 be a root of the equation 2 x^2+x-2=0 . If _ x 1 a 16 (1- (2+x-2 x^2 ) ) (1- a x)^2 = + 17 , where , Z , then + is equal to_______

Correct answer

0

Step-by-step solution

aligned & _ x 1 a 16 (1- 2 (x- 1 a ) (x- 1 b ) ) 4 (x- 1 b )^2 4 (x- 1 b )^2 a^2 (x- 1 a )^2 & =16 2 a^2 ( 1 a - 1 b )^2 & = 32 a^2 ( 17 4 )= 17.8 a^2 = 17 8 16 (-1+ 117 )^2 & = 136.16 18.2 7 18+2 7 18+2 7 & = 136 256 (18+2 7 ) 16 & =153+17 17 = + 17 & + =153+17=170 aligned

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