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JEE Main202127 Jul 2021Morning ShiftMathematicsLimitsActual

Let f : R → R be a function such that f 2 = 4 and f ' 2 = 1 . Then, the value of lim x → 2 x 2 f 2 - 4 f x x - 2 is equal to:

Options

  1. A4
  2. B8
  3. C16
  4. D12

Correct answer

D. 12

Step-by-step solution

Given, f 2 = 4 So, the given limit is in 0 0 form. So, lim x → 2 x 2 f 2 - 4 f x x - 2 Apply L 'Hospital Rule lim x → 2 2 x f 2 - 4 f ' x 1 = 4 4 - 4 1 = 12

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