JEE Main20202 Sep 2020Evening ShiftMathematicsLimitsActual
lim x → 0 tan π 4 + x 1 / x is equal to
Options
- Ae
- B2
- C1
- De 2
Correct answer
D. e 2
Step-by-step solution
lim x → 0 tan π 4 + x 1 / x                   1 ∞ form = e lim x → 0 tan π 4 + x - 1 x                           lim x → a f x g x = e lim x → a g x f x - 1 ,   lim x → a f x = 1   &   lim x → a g x = ∞ = e lim x → 0 1 + tan x 1 - tan x - 1 x = e lim x → 0 2 tan x x 1 - tan x   = e lim x → 0 tan x x 2 1 - tan