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JEE Main20208 Jan 2020Morning ShiftMathematicsLimitsActual

lim x → 0 3 x 2 + 2 7 x 2 + 2 1 x 2 is equal to

Options

A1 e
B1 e 2
Ce 2
De

Correct answer

B. 1 e 2

Step-by-step solution

Let L = l i m x → 0 3 x 2 + 2 7 x 2 + 2 1 x 2 = e lim x → 0 1 x 2 3 x 2 + 2 7 x 2 + 2 - 1 = e lim x → 0 - 4 x 2 7 x 2 + 2 = e - 4 2 = e - 2 = 1 e 2

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