JEE Main2015MathematicsLimitsActual
lim x → 0 1 - cos 2 x 3 + cos x x tan 4 x =
Options
- A1 2
- B4
- C3
- D2
Correct answer
D. 2
Step-by-step solution
lim x → 0 ⁡ ( 1 - cos ⁡ 2 x )     ( 3 + cos ⁡ x ) x tan ⁡ 4 x =   lim x → 0 ⁡ 2 sin 2 ⁡ x   ⋅ ( 3 + cos ⁡ x ) x ⋅ tan ⁡ 4 x =   lim x → 0 ⁡ 2 ⋅ sin ⁡ x x 2 ⋅ 3 + cos x tan ⁡ 4 x 4 x   ⋅ 4 =   2 ⋅ 1 2   ⋅ ( 3 + 1 ) 1   ⋅ 4 = 2 .