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JEE Main2003MathematicsLimitsActual

_ x 2 [1- ( x 2 ) ][1- x] [1+ ( x 2 ) ] [ -2 x^3 ] is

Options

  1. A1 8
  2. B0
  3. C1 32

Correct answer

3

Step-by-step solution

_ x 2 ( 4 - x 2 ) (1- x) ( -2 x)^3 Let x = 2 + y ; y 0= _ y 0 - (- y 2 ) (1- y) (-2 y)^3 = _ y 0 - y 2 2 ^2 y 2 (-8) y^3 8 8 = _ y 0 1 32 y 2 ( y 2 ) [ y / 2 y / 2 ]^2= 1 32

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