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JEE Main201910 Jan 2019Evening ShiftMathematicsTrigonometric Ratios & IdentitiesActual

The value of cos ⁡ π 2 2 ⋅ cos ⁡ π 2 3 ⋅ … ⋅ cos ⁡ π 2 10 ⋅ sin ⁡ π 2 10 is:

Options

  1. A1 1024
  2. B1 512
  3. C1 2
  4. D1 256

Correct answer

B. 1 512

Step-by-step solution

Given c o s π 2 2 · c o s π 2 3 · . . . · c o s π 2 10 · s i n π 2 10 = sin 2 9 . π 2 10 2 9 . sin π 2 10 . sin π 2 10 Using     cos A . cos 2 A . cos 2 2 A . cos 2 3 A . cos 2 4 A . . . . . cos 2 n - 1 A = sin 2 n A 2 n sin A = 1 2 9 = 1 512

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