Two capacitors of capacities 2C and C are joined in parallel and...

Two capacitors of capacities

2C

and

C

are joined in parallel and charged up to potential

V .

The battery is removed and the capacitor of capacity

C

is filled completely with a medium of dielectric constant

K .

The potential difference across the capacitors will now be: Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V . The battery is removed and

Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V . The battery is removed and

Options

A $\dfrac{V}{K + 2}$
B $\dfrac{V}{K}$
C $\dfrac{3V}{K + 2}$
D $\dfrac{3V}{K}$

Correct answer

C. $\dfrac{3V}{K + 2}$

Step-by-step solution

Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V . The battery is removed and

Now,

Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V . The battery is removed and

${V}_{C} = \dfrac{2CV + CV}{KC + 2C}$

$= \dfrac{3V}{K + 2}$

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